本篇文章主要介绍了php利用嵌套数组拼接与解析json的方法，小编觉得挺不错的，现在分享给大家，也给大家做个参考。一起跟随小编过来看看吧
利用嵌套数组 拼接混合json -包含对象数组
// 自 PHP 5.4 起
$array = [
"status" => "0","message" => "ok","arr"=> []
];
class Person {
public $name;
public $age;
//定义一个构造方法初始化赋值
public function __construct($name,$age) {
$this->name=$name;
$this->age=$age;
}
}
for($i=0;$i<10;$i++)
{
$p=new Person("ren",$i);
$array["arr"][]=$p;
}
//var_dump($array);
echo json_encode($array);
?>
PHP利用嵌套数组 解析混合json 包含对象数组
$v) {
if(is_object($v)) $arr[$k]=json_to_array($v); //判断类型是不是object
else $arr[$k]=$v;
}
return $arr;
}
$s='{"webname":"homehf","url":"www.homehf.com","qq":"744348666"}';
//将字符转成JSON
$web=json_decode($s);
$arr=array();
foreach($web as $k=>$v)
$arr[$k]=$v;
echo "
";
print_r($arr);
echo "
";
$s='{"webname":"homehf","contact":{"qq":"744348666","mail":"nieweihf@163.com","xx":"xxxxxxx"}}';
$web=json_decode($s);
$arr=json_to_array($web);
echo "
";
print_r($arr);
echo "
";
/****
****/
$s='{"webname":"homehf","xx":"xxxxxxx"}}';
$web=json_decode($s);
echo '网站名称：'.$web->webname.'
网址：'.$web->url.'
联系方式：QQ-'.$web->contact->qq.' MAIL:'.$web->contact->mail;
echo '
';
/****
****/
$s='{"webname":"homehf","xx":"xxxxxxx"}}';
$web=json_decode($s);
echo json_encode($web);
$mys='{"status":"0","message":"ok","arr":[{"name":"ren","age":0},{"name":"ren","age":1},"age":2},"age":3},"age":4},"age":5},"age":6},"age":7},"age":8},"age":9}]}';
$myweb=json_decode($mys);
echo $myweb->status;
for($i=0;$i<10;$i++)
{
echo $myweb->arr[$i]->age;
echo '
';
}
?>
以上就是本文的全部内容，希望对大家的学习有所帮助，也希望大家多多支持编程之家。
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