Given two numbers represented as strings, return multiplication of the numbers as a string.Note: The numbers can be arbitrarily large and are non-nega
Given two numbers represented as strings,return multiplication of the numbers as a string.
Note: The numbers can be arbitrarily large and are non-negative.
题意：字符串的乘法。
思路：摹拟竖乘的思路，跟大数计算1样，先将字符串颠倒
class Solution {
public:
string multiply(string num1,string num2) {
reverse(num1.begin(),num1.end());
reverse(num2.begin(),num2.end());
int len1 = num1.size(),len2 = num2.size();
string ans(len1+len2+1,'0');
int tmp = 0;
for (int i = 0; i < len1; i++) {
int cur = num1[i] - '0';
tmp = 0;
for (int j = 0; j < len2; j++) {
int a = tmp + cur * (num2[j]-'0') + (ans[i+j]-'0');
tmp = a / 10;
ans[i+j] = a % 10 + '0';
}
int idx = len2;
while (tmp != 0) {
int a = tmp + (ans[i+idx]-'0');
tmp = a / 10;
ans[i+idx] = a % 10 + '0';
idx++;
}
}
while (!ans.empty() && ans.back() == '0')
ans.pop_back();
if (ans.empty()) return "0";
reverse(ans.begin(),ans.end());
return ans;
}
};
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